CH5 AF comments
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@ -429,8 +429,11 @@ investigations.
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\fmmdglossOPAMP
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The symptom for this is given as a low slew rate.
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%
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Slew rate for a circuit/component is the rate at which it changes an output voltage level (i.e. $\frac{\delta V}{\delta t} $).
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%
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This means that the op-amp will not react quickly to changes on its input terminals.
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This is a failure symptom that may not be of concern in a slow responding system like an
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instrumentation amplifier. However, where higher frequencies are being processed,
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a signal may be lost entirely.
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@ -78,9 +78,7 @@ A valid range for the output value of this circuit is assumed.
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%and voltages higher than a given threshold considered as HIGH.
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Because the amplifier inverts and the input is guaranteed positive any
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output voltage above or equal to zero would be erroneous.
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This would be an `$AMP_{HIGH}$' failure symptom.
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output voltage above or equal to zero would be erroneous i.e. an `$AMP_{HIGH}$' failure symptom.
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%
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A threshold would be determined for an `$AMP_{LOW}$' failure symptom (i.e. the output voltage more negative than expected). % error given the expected input range.
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%
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@ -183,7 +181,8 @@ The final stage of analysis for this amplifier, is made by
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by forming a {\fg} with the OpAmp and the new {\dc} $IPD$.
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%
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\begin{table}[h+]
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\caption{Inverting Amplifier: Single failure analysis using the $PD$ {\dc}}
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\centering
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\caption{Inverting Amplifier: Single failure analysis using the $IPD$ {\dc}}
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\begin{tabular}{|| l | l | c | c | l ||} \hline
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%\textbf{Failure Scenario} & & \textbf{Inverted Amp Effect} & & \textbf{Symptom} \\ \hline
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\textbf{Failure} & & \textbf{Inverted Amp. Effect} & & \textbf{Symptom} \\
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@ -460,7 +459,10 @@ This means R3 R4 is not a fixed potential divider, with R4 being on the positive
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%
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It could be at either polarity. % (i.e. the other way around R4 could be the negative side).
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%
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Here it is more intuitive to model the resistors not as a potential divider, but individually.
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Here, even though R3 and R4 are used as a potential divider,
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it could be either inverted or non-inverted according to the voltages on the inputs.
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Therefore the resistors cannot modelled as a potential divider, but must be placed in the {\fg}
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with the OpAmp and analysed.
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%This means we are either going to
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%get a high or low reading if R3 or R4 fail.
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@ -661,6 +663,7 @@ The first order low pass filter is analysed in table~\ref{tbl:firstorderlpass}.\
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\begin{table}[h+]
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\centering
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\caption{FirstOrderLP: Failure Mode Effects Analysis: Single Faults} % title of Table
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\label{tbl:firstorderlpass}
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@ -821,7 +824,7 @@ and these are marked on the circuit schematic in figure~\ref{fig:circuit2002_FIV
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\label{fig:circuit2002_FIVEPOLE}
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\end{figure}
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%
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\pagebreak[4]
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%\pagebreak[4]
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%
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So the final {\fg} will consist of the derived components $\{ LP1, SKLP_1, SKLP_2 \}$.
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@ -1214,7 +1217,7 @@ increases the potential for re-use. % of pre-analysed {\dcs}.
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%
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A finer grained model---with potentially more hierarchy stages---also means that
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%more work, or
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more reasoning stages have been used in the analysis.
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more reasoning stages, i.e. FMMD analysis stages with their associated analysis reports, have been used in the analysis.
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% HTR The more we can modularise, the more we decimate the $O(N^2)$ effect
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% HTR of complexity comparison.
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%
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@ -1227,7 +1230,7 @@ However, it involves a large reasoning distance, the final stage
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having 24 failure modes to consider against each of the other seven {\dcs}.
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A finer grained approach produces more potentially re-usable {\dcs} and
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involves several stages with lower reasoning distances.
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The lower reasoning distances, or complexity comparision figures are given in the metrics chapter~\ref{sec:chap7}
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The lower reasoning distances, or complexity comparison figures are given in the metrics chapter~\ref{sec:chap7}
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at section~\ref{sec:bubbaCC}.
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These show that the finer grained models also benefit from lower reasoning distances for the failure mode model.
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@ -1731,7 +1734,7 @@ expected voltages for failure mode and temperature reading purposes.
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\begin{equation}
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\label{eqn:vd}
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V_{out} = V_{in}.\frac{Z2}{Z2+Z1}
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V_{out} = V_{in}.\frac{Z_2}{Z_2+Z_1}
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\end{equation}
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\subsection{Safety case for 4 wire circuit: Detailed calculations}
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@ -1843,8 +1846,8 @@ As the voltage over $R_3$ is relative (a design feature to eliminate resistance
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the current can be calculated by reading
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the voltage over the known resistor
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$R2$.\footnote{To calculate the resistance of the Pt100 we need the current flowing though it.
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This can be determined via Ohms law applied to $R_2$, $V=IR$, $I=\frac{V}{R_2}$,
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and then using $I$, with $I$, $R_{3} = \frac{V_{R3}}{I}$.}
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This can be determined via Ohms law applied to $R_2$, $V=I R_2$, $I=\frac{V}{R_2}$,
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and then using $I$, $R_{3} = \frac{V_{R3}}{I}$.}
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As these calculations are performed by Ohms law, which is linear, the accuracy of the reading
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will be determined by the accuracy of $R_2$ and $R_{3}$.
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%It is reasonable to
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