better description of why some primes dissappear under addition

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Robin P. Clark 2015-06-29 15:02:35 +01:00
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@ -100,26 +100,40 @@ this can be re-written as:
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% ADDITION DESTROY UNCOMMON PRIME FACTORS
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This means for $a^n+b^n$ the only prime factors guaranteed to be in $c^n$
are are those common in $a$ and $b$.
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Adding numbers creates a `dissolving' of prime factors in the result:
that is addition of numbers causes the uncommon prime factors to become
lost, but increases the number other prime factors.
lost.
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Consider $43 +21 = 64$. These primes add up to a result with
a bag of six twos i.e. $bpf(64) = \{2,2,2,2,2,2\}$ or more conventionally $64=2^6$.
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Prime numbers are unique. Adding to them, or adding other prime numbers to them, takes that unique
property away.
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If a prime is added to another prime number the result
cannot be a prime number, simply because all prime numbers above two are odd;
the result of the addition must even and therefore have at least a prime factor of two.
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Prime numbers are unique. Adding to them, or adding other prime numbers to them, takes that unique
property away.
Further, if numbers are added, the prime factors of the
result will not contain any of the uncommon primes.
That is the only prime factors preserved in the result of addition of $a$ and $b$
are the common ones, i.e. cbpf(a,b).
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%consider
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Thus only common prime factors in $a$ and $b$ are preserved
as a result of equation~\ref{eqn:primesexpanded1}.
This is simply because in addition
the common prime factors can be extracted, $a+b \equiv \prod bfp(a) + \prod bfp(b)$
re-writing $\prod cbpf(a,b) \big( \prod ubpf(a) + \prod ubpf(b) \big)$:
This means the uncommon prime factors of $\big( \prod ubpf(a) + \prod ubpf(b) \big)$
are lost and the $\prod cbpf(a,b)$ preserved.
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%
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This means for $a+b$ and $a^n+b^n$ the only prime factors preserved (i.e. in $c^n$)
are those common to $a$ and $b$.
\subsection{Conditions for having a integer root}