better description of why some primes dissappear under addition
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@ -100,26 +100,40 @@ this can be re-written as:
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% ADDITION DESTROY UNCOMMON PRIME FACTORS
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This means for $a^n+b^n$ the only prime factors guaranteed to be in $c^n$
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are are those common in $a$ and $b$.
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Adding numbers creates a `dissolving' of prime factors in the result:
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that is addition of numbers causes the uncommon prime factors to become
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lost, but increases the number other prime factors.
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lost.
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Consider $43 +21 = 64$. These primes add up to a result with
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a bag of six twos i.e. $bpf(64) = \{2,2,2,2,2,2\}$ or more conventionally $64=2^6$.
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Prime numbers are unique. Adding to them, or adding other prime numbers to them, takes that unique
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property away.
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If a prime is added to another prime number the result
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cannot be a prime number, simply because all prime numbers above two are odd;
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the result of the addition must even and therefore have at least a prime factor of two.
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Prime numbers are unique. Adding to them, or adding other prime numbers to them, takes that unique
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property away.
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Further, if numbers are added, the prime factors of the
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result will not contain any of the uncommon primes.
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That is the only prime factors preserved in the result of addition of $a$ and $b$
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are the common ones, i.e. cbpf(a,b).
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%
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%consider
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Thus only common prime factors in $a$ and $b$ are preserved
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as a result of equation~\ref{eqn:primesexpanded1}.
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This is simply because in addition
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the common prime factors can be extracted, $a+b \equiv \prod bfp(a) + \prod bfp(b)$
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re-writing $\prod cbpf(a,b) \big( \prod ubpf(a) + \prod ubpf(b) \big)$:
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This means the uncommon prime factors of $\big( \prod ubpf(a) + \prod ubpf(b) \big)$
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are lost and the $\prod cbpf(a,b)$ preserved.
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This means for $a+b$ and $a^n+b^n$ the only prime factors preserved (i.e. in $c^n$)
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are those common to $a$ and $b$.
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\subsection{Conditions for having a integer root}
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