42 lines
970 B
Python
42 lines
970 B
Python
import math
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j = 1j
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def model_c(w,C):
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Z = 1.0/(j*w*C)
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return Z
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#
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# Model the reactance of an RC parallel circuit.
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#
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def model_r_c_p(w, R, C):
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# Z2 is the straight parallel equation that python can handle
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Z2 = (1.0)/((1.0/R)+(1.0)/((1.0)/(j*w*C)))
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# Z is the equation easier to implement in C (just rearranged)
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# i.e. it has a real divisor
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Z = ((1.0/R)-j*w*C)/((1.0/R)**2 + (w*C)**2)
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#return Z2,Z for comparison return both and check they give the same results
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return Z#, Z2
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# return magnitude of RC in parallel
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# from https://www.translatorscafe.com/unit-converter/EN/calculator/parallel-rc-impedance/
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#
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def model_k(w, R, C):
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Z = 1.0/(math.sqrt((1.0/R)**2 + (w*C)**2))
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return Z
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R = 220
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C = 10E-6
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for f in range (1,3000000, 20):
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print f
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w = 2 * 3.142 * f
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Z = model_r_c_p (w,R,C)
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#Z = model_c(w,C)
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#Z = model_k(w,R,C)
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#print "at freq", f, Z#, abs(Z)
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print "at freq", f, Z, abs(Z)
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#print Z
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