components with independent failure modes

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Robin Clark 2011-01-10 14:16:57 +00:00
parent 860607b1ef
commit f0434f9463
7 changed files with 71 additions and 1 deletions

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@ -734,6 +734,76 @@ component failure modes $\{ B_1 ... B_8, OK \}$ obeying unitary state conditions
\label{fig:partitioncfm}
\end{figure}
\section{Components with Independent failure modes}
Suppose that we have a component that can fail simultaneously
with more than one failure mode.
This would make it seemingly impossible to model as `unitary state'.
\paragraph{De-composition of complex component.}
There are two ways in which we can deal with this.
We could consider the component a composite
of two simpler components, and model their interaction to
create a derived component.
\begin{figure}[h]
\centering
\includegraphics[width=200pt,bb=0 0 353 247,keepaspectratio=true]{./component_failure_modes_definition/compco.jpg}
% compco.jpg: 353x247 pixel, 72dpi, 12.45x8.71 cm, bb=0 0 353 247
\caption{Component with three failure modes as partitioned sets}
\label{fig:combco}
\end{figure}
\paragraph{Combinations become new failure modes.}
Alternatively, we could consider the combinations
of the failure modes as new failure modes.
We can model this using an Euler diagram representation of
an example component with three failure modes $\{ B_1, B_2, B_3, OK \}$ see figure \ref{fig:combco}.
For the purpose of example let us consider $\{ B_2, B_3 \}$
to be intrinsically mutually exclusive, by $B_1$ to be independent.
This means the we have the possibility of two new combinations
$ B_1 \cap B_2$ and $ B_1 \cap B_3$.
We can represent these
as shaded sections of figure \ref{fig:combco2}.
\begin{figure}[h]
\centering
\includegraphics[width=200pt,bb=0 0 353 247,keepaspectratio=true]{./component_failure_modes_definition/compco2.jpg}
% compco.jpg: 353x247 pixel, 72dpi, 12.45x8.71 cm, bb=0 0 353 247
\caption{Component with three failure modes where $B_1$ is independent}
\label{fig:combco2}
\end{figure}
We can calculate the probabilities for the shaded areas
assuming the failure modes are statistically independent
by multiplying the probabilities of the members of the intersection.
We can use the function $P$ to return the probability of a
failure mode, or combination thereof.
Thus for $P(B_1 \cap B_2) = P(B_1)P(B_2)$ and $P(B_1 \cap B_3) = P(B_1)P(B_3)$.
\begin{figure}[h]
\centering
\includegraphics[width=200pt,bb=0 0 353 247,keepaspectratio=true]{./component_failure_modes_definition/compco3.jpg}
% compco.jpg: 353x247 pixel, 72dpi, 12.45x8.71 cm, bb=0 0 353 247
\caption{Component with two new failure modes}
\label{fig:combco3}
\end{figure}
We can now consider the shaded areas as new failure modes of the component.
Because of the combinations, the probabilities for the failure modes
$B_1, B_2$ and $B_3$ will now reduce.
We can use the prime character ($/prime$), to represent the altered value for a failure mode, i.e.
$B_1^\prime$ represents the altered value for $B_1$.
Thus
$$ P(B_1^\prime) = B_1 - P(B_1 \cap B_2) - P(B_1 \cap B_3)\; , $$
$$ P(B_2^\prime) = B_2 - P(B_1 \cap B_2) \; and $$
$$ P(B_3^\prime) = B_3 - P(B_1 \cap B_3) \; . $$
@ -778,7 +848,7 @@ operational states.
Some failure modes may only be active given specific environmental conditions
or when other failures are already active.
To model this, an `inhibit' class has been added.
This is an optional atribute of
This is an optional attribute of
a failure mode. This inhibit class can be triggered
on a combination of environmental or failure modes.