added iterative fishing for primes method based on the addition of

uncommon factors removing primes in the result.
This commit is contained in:
Robin Clark 2015-07-06 22:55:55 +01:00
parent 3487ebe5ff
commit ca64383bd9

View File

@ -325,7 +325,45 @@ to get seven as a prime factor in the result.
Any other number will not give a 7 in the bag of prime numbers representation of the result. Any other number will not give a 7 in the bag of prime numbers representation of the result.
\section{Further work}
Using the rule of adding uncommon factors, an iterative `fishing' method for finding prime numbers can be applied.
An addition is made, and the lower prime factors of the result are added as uncommon factors in a subsequent addition
until finally a larger single prime number is found.
This can be done with single primes, or for finding larger primes in less iterations, with multiple powers of primes.
For example consider
%
starting with the first two uncommon primes squared,
$$\prod \{2,2\} + \prod \{3,3\} = \{13\};$$
this gives the prime number 13.
%octave:26> factor(2^2+3^2)
%ans = 13
%
%
%octave:28> factor(2^2+3^2*13^2)
%ans =
By placing 13 squared as an uncommon factor, more primes are shaken out:
$$\prod \{2,2\} + \prod \{3,3,13,13\} = \prod \{5,5,61\}.$$
%
Making the prime number 5 uncommon in the addition gives:
$$\prod \{2,2\} + \prod \{3,3,5,5,13,13\} = \prod \{17,2237\};$$
%octave:29> factor(2^2+3^2*13^2*5^2)
%ans =
%
removing the 17 by making it an uncommon factor in the addition:
% 17 2237
$$\prod \{2,2\} + \prod \{3,3,5,5,13,13,17,17\} = \{10989229\};$$
%octave:30> factor(2^2+3^2*13^2*5^2*17^2)
%$ans = 10989229
gives a larger prime number 10989229 and so on.
\subsection{fishing with cubic primes}
Fishing with primes cubes reveals larger primes quicker: take
$$ \prod \{2,2,2,5,5,5,11,11,11\} + \prod \{3,3,3,7,7,7,13,13,13\} = \prod \{ 383 , 56599 \} \; ,$$
Adding 56599 as a single uncommon factor;
$$ \prod \{2,2,2,5,5,5,11,11,11\} + \prod \{3,3,3,7,7,7,13,13,13,56599\} = \prod \{ 151, 359, 1553, 13679 \} \; , $$
Removing 359 reveals a large prime:
$$ \prod \{2,2,2,5,5,5,11,11,11\} + \prod \{3,3,3,7,7,7,13,13,13,56599,359\} = \{413419682557097\} $$
% %
% \begin{equation} % \begin{equation}