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Robin Clark 2010-10-09 20:08:17 +01:00
parent 3fc2688764
commit 7e6f1477d6

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@ -104,8 +104,10 @@ An offset is applied to the input by R18 and R22 forming a potential divider
of $\frac{820}{2.2E6+820}$. With 5V applied as Vcc this gives an input offset of $1.86\,mV$. of $\frac{820}{2.2E6+820}$. With 5V applied as Vcc this gives an input offset of $1.86\,mV$.
So the amplified offset is $\approx 342 \, mV$. We can determine the output of the amplifier So the amplified offset is $\approx 342 \, mV$. We can determine the output of the amplifier
by subtracting this amount from the reading. We can also define an acceptable by subtracting this amount from the reading. We can also define an acceptable
range for the readings. This would depend on the milli-volt source, and also on the range for the readings. This would depend on the characteristics of milli-volt source, and also on the
detectability of the error volatges. thresholds of the volatges considered out of range. For the sake of example let us
consider this to be a type K thermocouple amplifier, with a range of temperatures
expected to be within {{0}\oc} and {{300}\oc}.
EXPAND EXPAND