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@ -104,8 +104,10 @@ An offset is applied to the input by R18 and R22 forming a potential divider
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of $\frac{820}{2.2E6+820}$. With 5V applied as Vcc this gives an input offset of $1.86\,mV$.
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of $\frac{820}{2.2E6+820}$. With 5V applied as Vcc this gives an input offset of $1.86\,mV$.
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So the amplified offset is $\approx 342 \, mV$. We can determine the output of the amplifier
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So the amplified offset is $\approx 342 \, mV$. We can determine the output of the amplifier
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by subtracting this amount from the reading. We can also define an acceptable
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by subtracting this amount from the reading. We can also define an acceptable
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range for the readings. This would depend on the milli-volt source, and also on the
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range for the readings. This would depend on the characteristics of milli-volt source, and also on the
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detectability of the error volatges.
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thresholds of the volatges considered out of range. For the sake of example let us
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consider this to be a type K thermocouple amplifier, with a range of temperatures
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expected to be within {{0}\oc} and {{300}\oc}.
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EXPAND
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EXPAND
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