diff --git a/component_failure_modes_definition/component_failure_modes_definition.tex b/component_failure_modes_definition/component_failure_modes_definition.tex
index ffb7d42..c18c9a8 100644
--- a/component_failure_modes_definition/component_failure_modes_definition.tex
+++ b/component_failure_modes_definition/component_failure_modes_definition.tex
@@ -339,23 +339,6 @@ Thus if the failure modes of  a component $F$ are unitary~state, we can say $F \
 An example of a component with an obvious set of  ``unitary~state'' failure modes is the electrical resistor.
 
 Electrical resistors can fail by going OPEN or SHORTED.
-%% CUNT 
-%% CUNT For a given resistor R we can apply the 
-%% CUNT the function $fm$ to find its set of failure modes thus  $ fm(R) =  \{R_{SHORTED}, R_{OPEN}\} $.
-%% CUNT A resistor cannot fail with both conditions open and short active at the same time! The conditions
-%% CUNT OPEN and SHORT are thus mutually exclusive.
-%% CUNT Because of this, the failure mode set $F=fm(R)$ is `unitary~state'.
-%% CUNT 
-%% CUNT 
-%% CUNT Thus because both fault modes cannot be active at the same time, the intersection of $ R_{SHORTED} $ and $ R_{OPEN} $ cannot exist.
-%% CUNT 
-%% CUNT  The intersection of these is therefore the empty set, $$ R_{SHORTED} \cap R_{OPEN} \eq \emptyset $$,
-%% CUNT therefore
-%% CUNT $ fm(R) \in \mathcal{U} $.
-%% CUNT 
-%% CUNT 
-
-
  
 For a given resistor R we can apply the 
 the function $fm$ to find its set of failure modes thus  $ fm(R) =  \{R_{SHORTED}, R_{OPEN}\} $.
@@ -366,7 +349,6 @@ Because of this, the failure mode set $F=fm(R)$ is `unitary~state'.
 
 Thus because both fault modes cannot be active at the same time, the intersection of $ R_{SHORTED} $ and $ R_{OPEN} $ cannot exist.
  
-%%CUNT The intersection of these is therefore the empty set, $$ R_{SHORTED} \cap R_{OPEN} \eq \emptyset $$,
 The intersection of these is therefore the empty set, $$ R_{SHORTED} \cap R_{OPEN} = \emptyset $$,
 therefore
 $ fm(R) \in \mathcal{U} $.
@@ -578,12 +560,6 @@ components $C_j$ are in
 \end{itemize}
 %}
 
-%% CUNT 
-%% CUNT \begin{equation}
-%% CUNT  |{\mathcal{P}_{cc}SU}| = {\sum^{cc}_{k=1}  \frac{|{SU}|!}{k!(|{SU}| - k)!}}  
-%% CUNT - {\sum{j \in J} {|FM({C_{j})}| \choose 2}}} 
-%% CUNT  \label{eqn:correctedccps}
-%% CUNT \end{equation}
 \begin{equation}
   |{\mathcal{P}_{cc}SU}| = {\sum^{cc}_{k=1}  \frac{|{SU}|!}{k!(|{SU}| - k)!}}  
  - {\sum_{j \in J} {|FM({C_{j})}| \choose 2}} 
@@ -667,7 +643,7 @@ Thus the statistical sample space $\Omega$ for a component or derived~component
 $$ \Omega(C) = \{OK, failure\_mode_{1},failure\_mode_{2},failure\_mode_{3}, \ldots ,failure\_mode_{N}\} $$
 The failure mode set $F$ for a given component or derived~component $C$
 is therefore
-$$ F = \Omega(C) \backslash OK $$
+$$ F = \Omega(C) \backslash \{OK\} $$
 
 The $OK$ statistical case is the largest in probability, and is therefore
 of interest when analysing systems from a statistical perspective.