From 4ec18c0321355c9f7786826127dd26e98ce16dd0 Mon Sep 17 00:00:00 2001 From: Robin Clark Date: Thu, 7 Oct 2010 19:37:03 +0100 Subject: [PATCH] . --- fmmd_design_aide/fmmd_design_aide.tex | 4 ++-- 1 file changed, 2 insertions(+), 2 deletions(-) diff --git a/fmmd_design_aide/fmmd_design_aide.tex b/fmmd_design_aide/fmmd_design_aide.tex index 9bede21..f1f7fe8 100644 --- a/fmmd_design_aide/fmmd_design_aide.tex +++ b/fmmd_design_aide/fmmd_design_aide.tex @@ -76,7 +76,7 @@ We then analsye the {\fg} and the resultant {\dc} failure modes are discussed. \begin{figure}[h] \centering - \includegraphics[width=200pt,bb=0 0 678 690,keepaspectratio=true]{./mv_opamp_circuit.png} + \includegraphics[width=200pt,bb=0 0 678 690,keepaspectratio=true]{./fmmd_design_aide/mv_opamp_circuit.png} % mv_opamp_circuit.png: 678x690 pixel, 72dpi, 23.92x24.34 cm, bb=0 0 678 690 \caption{Milli-Volt Amplifier with Safety/Offset Resistor} \label{fig:mv1} @@ -86,7 +86,7 @@ We then analsye the {\fg} and the resultant {\dc} failure modes are discussed. This circuit amplifies a milli-volt input by a gain of $\approx$ 184 ($\frac{150E3}{820}+1$). An offset is applied to the input by R18 and R22 forming a potential divider -of $\frac{820}{2.2E6+820}$. Will 5V applied as Vcc this gives an input offset of 1.86mV. +of $\frac{820}{2.2E6+820}$. With 5V applied as Vcc this gives an input offset of 1.86mV. So the amplified offset is $\approx 342mV$. We can determine the output of the amplifier by subtracting this amount from the reading. We can also define an acceptable range for the readings. This would depend on the milli-volt source, and also on the